+0  
 
0
462
1
avatar+56 

A bag contains 11 candy bars: three cost 50 cents each, four cost $1 each and four cost $2 each. How many ways can 3 candy bars be selected from the 11 candy bars so that the total cost is more than $4?

 

Need answer AND Explination as soon as possible please!!!!! Thank you!!!!!!

Trinityvamp286  Jul 17, 2017
 #1
avatar+89803 
+1

 

 

Looking at each candy bar as a unique item, we have C(11,3) = 165  total ways to choose  any three of them

 

More than $4

 

$6 = Choose any three of the four $2 ones  =  C(4,3) = 4 ways

 

$5 = Choose any two of the four $2 ones and any one of the four  $1 ones  = C(4,2) * C(4,1)  = 24 ways

 

$4.50 =  Choose any two of the four $2 ones and any one of the three  $.50 ones  = C(4,2) * C(3,1)  = 18 ways

 

So....the total ways are  4 + 24 + 18  =   46 ways

 

 

cool cool cool

CPhill  Jul 17, 2017

16 Online Users

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.