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A bag contains 11 candy bars: three cost 50 cents each, four cost $1 each and four cost $2 each. How many ways can 3 candy bars be selected from the 11 candy bars so that the total cost is more than $4?

 

Need answer AND Explination as soon as possible please!!!!! Thank you!!!!!!

Trinityvamp286  Jul 17, 2017
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Looking at each candy bar as a unique item, we have C(11,3) = 165  total ways to choose  any three of them

 

More than $4

 

$6 = Choose any three of the four $2 ones  =  C(4,3) = 4 ways

 

$5 = Choose any two of the four $2 ones and any one of the four  $1 ones  = C(4,2) * C(4,1)  = 24 ways

 

$4.50 =  Choose any two of the four $2 ones and any one of the three  $.50 ones  = C(4,2) * C(3,1)  = 18 ways

 

So....the total ways are  4 + 24 + 18  =   46 ways

 

 

cool cool cool

CPhill  Jul 17, 2017

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