Two cars leave Phoenix and travel along roads 90 degrees apart. If Car 1 leaves 30 minutes earlier than Car 2 and averages 42 mph and if Car 2 averages 50 mph, how far apart will they be after Car 1 has traveled 3.5 hours?
+36916 Car 1 distance = 42 m/h x 3.5 hr = 147 m
Car 2 = 50 m/h x 3 hr = 150 m
Now use pythagorean theorem d = sqrt ( 147^2 + 150^2) = 210 miles
