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Two cars leave Phoenix and travel along roads 90 degrees apart. If Car 1 leaves 30 minutes earlier than Car 2 and averages 42 mph and if Car 2 averages 50 mph, how far apart will they be after Car 1 has traveled 3.5 hours?

 Mar 6, 2020
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Car 1 distance = 42 m/h  x 3.5 hr = 147 m

Car 2                = 50 m/h x 3 hr = 150 m

 

Now use pythagorean theorem     d = sqrt ( 147^2 + 150^2) = 210 miles

 Mar 6, 2020

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