PLEASE HELP!

14A6₁₂ - 5B9₁₂  =  ?                                           A₁₂ = 10_ten     B₁₂ = 11_ten

 

You can first change each of these into base ten:

     14A6₁₂  =  (1·12³) + (4·12²) + (10·12) + 6  =  2430

       5B9₁₂  =  (5·12²) + (11·12) + 9                 =     861

 

    2430 - 861  =  1569

 

Now change 1569₁₀  into base twelve:

     1569 / 12  =  130, remainder 9

       130 / 12  =  10,   remainder A

          10 /12  =  0,     remainder A

 

Answer:  AA9

AA9_{12} is right.

 

The WolframAlpha computation: https://www.wolframalpha.com/input/?i=14A6+base+12+-+5B9+base+12