\(\frac{-5\pm i\sqrt{11}}{6}\)
3x^2 + 5x + k
The product of the two roots is
(-5 + i√11) / 6 * (-5 - i√11) / 6 = (25 - i^2* 11)/ 36 = (25 - (-1)(11) ) / 36 =
[25 + 11] / 36 = 36 / 36 = 1
And this product will equal k/3
So
k/3 = 1 multiply both sides by 3
k = 3
+610 
