Determine the number of five-digit integers (37abc) in base 10 such that each of the numbers (37bca), (37cab) and (37cab) is divisible by 37.
37037 , 37074 , 37148 , 37185 , 37259 , 37296 , 37370 , 37407 , 37481 , 37518 , 37592 , 37629 , 37703 , 37740 , 37814 , 37851 , 37925 , 37962 = 18 such numbers
Thak you so much! :)
+113 
