+0

0
101
1

How do you get from ( |z| )^2 = a^2 + b^2 to -2z = -2a + 2i - b

Sep 14, 2018

#1
+99377
+2

How do you get from ( |z| )^2 = a^2 + b^2 to -2z = -2a + 2i *- b

You missed the times sign.

$$z=a+bi\\ \text{|z| is the distance of point Z from the origin.}\\ \text{Using pythagorases theorem we get }|z|^2=a^2+b^2\\ \\~\\ Since z=a+bi\\ -2z=-2(a+bi)\\ -2z=-2a-2bi$$

.
Sep 15, 2018