+0  
 
+5
638
3
avatar

Solve for b and c using addition or substitution

 

159 b + 3.3 c = 1000 mg

2.3 b + 0.3 c = 18 mg

 Sep 18, 2015

Best Answer 

 #2
avatar+23254 
+5

To solve by addition or subtraction, you need to coefficients of either term to be the same (or negatives of each other).

If you multiply 0.3 by 11, you get 3.3, which will allow you to cancel out the c terms.

159 b + 3.3 c  =  1000   --->  leave this alone   --->   159 b + 3.3 c  =  1000

 2.3 b + 0.3 c  =  18      --->   times 11     --->          25.3 b + 3.3 c  =  198

Subtract down the columns:                                  133.7 b            =  802

Divide by 133.7:                                                                    b   =  5.9985  (approximately)

Substitute this value into either equation:  2.3 b + 0.3 ( 5.9985)  =  18      --->   b  =  14.011 (approximately)

 Sep 18, 2015
 #1
avatar
+5

 

b = 5.9985 and c = 14.0115

 Sep 18, 2015
 #2
avatar+23254 
+5
Best Answer

To solve by addition or subtraction, you need to coefficients of either term to be the same (or negatives of each other).

If you multiply 0.3 by 11, you get 3.3, which will allow you to cancel out the c terms.

159 b + 3.3 c  =  1000   --->  leave this alone   --->   159 b + 3.3 c  =  1000

 2.3 b + 0.3 c  =  18      --->   times 11     --->          25.3 b + 3.3 c  =  198

Subtract down the columns:                                  133.7 b            =  802

Divide by 133.7:                                                                    b   =  5.9985  (approximately)

Substitute this value into either equation:  2.3 b + 0.3 ( 5.9985)  =  18      --->   b  =  14.011 (approximately)

geno3141 Sep 18, 2015
 #3
avatar
+5

Thank you both. I've had so much confusion trying to solve this one. I appreciate your help!

 Sep 18, 2015

1 Online Users