Solve for b and c using addition or substitution
159 b + 3.3 c = 1000 mg
2.3 b + 0.3 c = 18 mg
To solve by addition or subtraction, you need to coefficients of either term to be the same (or negatives of each other).
If you multiply 0.3 by 11, you get 3.3, which will allow you to cancel out the c terms.
159 b + 3.3 c = 1000 ---> leave this alone ---> 159 b + 3.3 c = 1000
2.3 b + 0.3 c = 18 ---> times 11 ---> 25.3 b + 3.3 c = 198
Subtract down the columns: 133.7 b = 802
Divide by 133.7: b = 5.9985 (approximately)
Substitute this value into either equation: 2.3 b + 0.3 ( 5.9985) = 18 ---> b = 14.011 (approximately)
To solve by addition or subtraction, you need to coefficients of either term to be the same (or negatives of each other).
If you multiply 0.3 by 11, you get 3.3, which will allow you to cancel out the c terms.
159 b + 3.3 c = 1000 ---> leave this alone ---> 159 b + 3.3 c = 1000
2.3 b + 0.3 c = 18 ---> times 11 ---> 25.3 b + 3.3 c = 198
Subtract down the columns: 133.7 b = 802
Divide by 133.7: b = 5.9985 (approximately)
Substitute this value into either equation: 2.3 b + 0.3 ( 5.9985) = 18 ---> b = 14.011 (approximately)