A manufacturer produces soda cans and a quality control worker randomly selects two cans from the assembly line for testing. Past statistics show that 14% of the cans are defective. What is the probability that the two selected cans are defective if the quality control worker selects the two cans from a batch of 50 cans?
A. P(Both defective) = 7/50
B. P(Both defective) = 49/2500
C. P(Both defective) = 3/175
D. P(Both defective) = 7/25
14%, or 14/100, or 7/50, of the cans are defective. 7 are defective in the batch of 50 cans. So, the probability of one being defective is 7/50. But if two are defective, that means that the probability is 7/50 times 7/50 because the faulty cans have to be selected twice. So the answer is B because 7 times 7 is 49 and 50 times 50 is 2500.
