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32(cos(7pi/4)+i sin(7pi/4))               

4root2(cos(5pi/6)+i sin(5pi/6))

 May 28, 2022
 #1
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help you do what?

 May 29, 2022
 #2
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I need to divide them

Guest May 30, 2022
 #3
avatar+118141 
+1

\(\frac{32(cos(7\pi/4)+i sin(7\pi/4))} {4\sqrt2(cos(5\pi/6)+i sin(5\pi/6))}\\~\\ = \frac{32(e^{(7\pi/4)i})} {4\sqrt2(e^{(5\pi/6)i})}\\~\\ = \frac{8(e^{(7\pi/4)i-(5\pi/6)i})} {\sqrt2}\\~\\ = 4\sqrt2(e^{(7\pi/4)i-(5\pi/6)i})\)

 

you can check and finish it.

 May 30, 2022

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