1)
In the middle of town, State and Elm streets meet at an angle of 40º. A triangular pocket park between the streets stretches 100 yards along State Street and 53.2 yards along Elm Street. The area of the pocket park to the nearest tenth of a square yard is ____ square yards.
2) Suppose a triangular silk scarf has both of its shortest sides 14 inches long. If the angle between these sides is 110º, what is the area of the scarf? Round your answer to the nearest tenth of a square inch. (Enter only the number.)
+129840 The area of the park is given by (1/2)(100)(53.2)sin(40°) = about 1709.8 square yards.
I answered the second one here : http://web2.0calc.com/questions/area-of-triangles-in-trigonometry#r1
+129840 The area of the park is given by (1/2)(100)(53.2)sin(40°) = about 1709.8 square yards.
I answered the second one here : http://web2.0calc.com/questions/area-of-triangles-in-trigonometry#r1
