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1. How many positive integers less than or equal to 6*7*8*9 solve the system of congruences:

$\begin{align*}
m &\equiv 5 \pmod{6}, \\
m &\equiv 4 \pmod{7}, \\
m &\equiv 3 \pmod{8}, \\
m &\equiv 3 \pmod{9}?
\end{align*}$

 Nov 20, 2020
 #1
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I found the answer now! so nevermind

 Nov 20, 2020
 #2
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Just gonna give you an image of cos(y)!

 Nov 20, 2020
 #3
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ugh next time im using my account. please don't pretend to be another person.

 Nov 20, 2020

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