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2(2r-1)/6+3=3(r+7)/18 please provide step by step

MarcoY0994  Aug 29, 2017
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2(2r-1)/6+3=3(r+7)/18

 

I'm taking literally what you wrote which is

 

2(2r -1)                     3(r + 7 )

______    +   3   =    _______                multiply through by 18  to clear the fractions

     6                             18

 

3 [ 2(2r -1) ]  +  54  =  3(r + 7 )          simplify

 

12r - 6   +  54  =  3r +  21

 

12r + 48  =  3r + 21          subtract   3r, 48 from  both sides

 

9r  = -27            divide both sides by 9

 

r  = -3

 

 

 

cool cool cool

CPhill  Aug 29, 2017

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