Please show me the work for this problem

Simplify the following:
(3^2×2^3)/3^3+3/3^3

Combine powers. (3^2×2^3)/3^3 = 3^(2-3)×2^3:
3^2-3×2^3+3/3^3

2-3 = -1:
3^-1×2^3+3/3^3

Combine powers. 3/3^3 = 3^(1-3):
2^3/3+3^1-3

1-3 = -2:
2^3/3+3^-2

2^3 = 2×2^2:
2×2^2/3+3^(-2)

2^2 = 4:
(2×4)/3+3^(-2)

2×4  =  8:
8/3+3^(-2)

3^(-2) = 1/9:
8/3+1/9

Put 8/3+1/9 over the common denominator 9. 8/3+1/9  =  (3×8)/9+1/9:
(3×8)/9+1/9

3×8  =  24:
24/9+1/9

24/9+1/9  =  (24+1)/9:
(24+1)/9

24+1 = 25:
Answer: |  25/9

(3^2*2^3)*3^-3+(3/3^3)

[(9*8) * 1/27] + [3/27] =

[72/27] + [3/27] =

75/27 = divide both sides by 3

25/9 =2 7/9

\(3^2\times2^3\times3^{-3}+\frac{3}{3^3}\)

\(=(3^{-3})(9\times8+3)\)

\(= \frac{75}{27}\)

\(=\frac{25}{9}\)

Please show me how to do the work for the question 25 divided by 4