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PLease show work for all questions if possible ​

18r^-3 / (6r^2 x 3r^3)

 

Options.

A.r^3

B.r^-6

C.r^-8

D1/r^-3

Please show me the work for each question if possible.

Question 2

 

This one is probably easy but its confusing me.

9^2 x 9^5

_________

 3^4 x 3^3

 

Question 3

 

m^4 x 3n^4 x 4m^2

__________________

2n x n^2 x 6m^2

 

Question 4

 

6^2 x 2^5 x 6^3

______________

12^3

 Sep 15, 2016

Best Answer 

 #1
avatar+55 
+9

Bro the reason no one is answering to your question is that you've posted your entire maths homework here. You're not asking for help to understand you're asking these people to literally do your homework so if you wanna learn how to do it yourself post only one of those problems and i will solve it with the work for each step and then you can apply the way I solved them in to the other problems (they're all quite similar).

 Sep 15, 2016
 #1
avatar+55 
+9
Best Answer

Bro the reason no one is answering to your question is that you've posted your entire maths homework here. You're not asking for help to understand you're asking these people to literally do your homework so if you wanna learn how to do it yourself post only one of those problems and i will solve it with the work for each step and then you can apply the way I solved them in to the other problems (they're all quite similar).

MattMayD Sep 15, 2016
 #3
avatar+22 
+5

blush Sorry if it seems that way i have to finish this tonight(yes its night time were i am)and its confusing me but THanks Melody and Matt for helping out.

NOTamathematician  Sep 15, 2016
 #2
avatar+118613 
+5

Yea Matt might be right but I will show you the first one.

 

18r^-3 / (6r^2 x 3r^3)

 

You can do this lots of ways and you SHOULD understand all of them

method

 

\(\frac{18r^{-3 }}{ 6r^2 \times 3r^3}\\ =\frac{18r^{-3-2-3 }}{ 6 \times 3} \qquad \text{if you are dividing terms you subtract indices}\\ =\frac{18r^{-8 }}{18} \\ =\frac{1r^{-8 }}{1} \\ =\frac{1}{1r^{+8}} \\ =\frac{1}{r^{8}} \\\)

 

Second method:

 

\(\frac{18r^{-3 }}{ 6r^2 \times 3r^3}\\~\\ =\frac{1*r^{-3 }}{ r^2 \times r^3}\\~\\ \text{If a term is raised to a negative power, swap it to the} \\ \text{other side of the fraction line and change the negative power to a positive power}\\ =\frac{1}{ r^2 \times r^3\times r^{+3 }}\\~\\ =\frac{1}{ r^{2 +3+3}}\\~\\ =\frac{1}{ r^{8}}\\~\\ \)

 

Now you should try the others yourself.

 Sep 15, 2016
 #4
avatar+118613 
0

NOTamathematician.

 

I just realized that you have asked this exact same question FIVE times in tha past hour.

Do you realize how rude that is!!

 

And, it has been answered on two different threads as well - what a waste of answeres time!

 

Do not do this again!!

If your questions falls way back in the line than you can do a new post with the address of the original post in it.

You are expected to wait a reasonable period of time, certainly more than an hour, AND your question should be way down from the top of the list! 

 

You new post can be called   'repeat request'  or something like that.

and you can state3 that you still really want help.

 

This is a teaching site.  The fact that you have homework and have to go to bed in 5 minutes is irrelevant to us.

 

Thank you for giving your answerers points and a sort of an appology.      laugh

Now that you understand I am sure you will not do it again.          laugh

 Sep 15, 2016
 #5
avatar+22 
+5

I feel horrible super sorry i didn't really think about the time i was making you guys waste defiantely will think before i postblush

NOTamathematician  Sep 15, 2016

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