Guest: how do you solve
(5x-3)/6-(2x-6)/5
are they meant to be x's or times signs.
I think mighty has takent them as times signs.
I'll assume that they are x's
[ (5x-3)/6 ] - [ (2x-6)/5 ]
You need a common denominator which will be 30
so it becomes
[ 5(5x-3)/30 ] - [ 6(2x-6)/30 ]
Can you take it from there?