3^(x + 1)* 2 = 108 divide both sides by 2
3^(x + 1) = 54 take the log of both sides
log 3^(x+ 1) = log 54 and we can write
(x + 1) log 3 = log 54 divide both sides by log 3
x + 1 = log54 / log 3 subtract 1 from both sides
x = log 54 / log 3 - 1 ≈ 2.63
However.....if this is supposed to be
3^[ (x + 1) * 2 ] = 54
3^( 2x + 2) = 54
3^(2x) * 3^2 = 54
3^(2x) * 9 = 54 divide both sides by 9
3^(2x) = 6 take the log of both sides
log 3 ^(2x) = log 6
(2x) log 3 = log 6
2x = log6 / log 3
x = log 6 / [2 log 3]
x = log 6 / [ log 3^2]
x = log 6 / log 9 ≈ .8155