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(x-3)/3 = -4+(1/2)

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 #1
avatar+4711 
+1

\(\frac{x-3}{3}\,=\,-4+\frac12\)

                                             Multiply both sides of the equation by  3  .

\(x-3\,=\,3(-4)+3(\frac12) \\~\\ x-3\,=\,-12+\frac32\)

                                             Add  3  to both sides of the equation.

\(x\,=\,-12+\frac32+3\)

                                             Get a common denominator on the right side and combine the fractions.

\(x\,=\,\frac{-12(2)}{2}+\frac{3}{2}+\frac{3(2)}{2} \\~\\ x\,=\,\frac{-24}{2}+\frac{3}{2}+\frac{6}{2} \\~\\ x\,=\,\frac{-24+3+6}{2}\\~\\ x\,=\,-\frac{15}{2}\)

hectictar  Oct 3, 2017
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1+0 Answers

 #1
avatar+4711 
+1
Best Answer

\(\frac{x-3}{3}\,=\,-4+\frac12\)

                                             Multiply both sides of the equation by  3  .

\(x-3\,=\,3(-4)+3(\frac12) \\~\\ x-3\,=\,-12+\frac32\)

                                             Add  3  to both sides of the equation.

\(x\,=\,-12+\frac32+3\)

                                             Get a common denominator on the right side and combine the fractions.

\(x\,=\,\frac{-12(2)}{2}+\frac{3}{2}+\frac{3(2)}{2} \\~\\ x\,=\,\frac{-24}{2}+\frac{3}{2}+\frac{6}{2} \\~\\ x\,=\,\frac{-24+3+6}{2}\\~\\ x\,=\,-\frac{15}{2}\)

hectictar  Oct 3, 2017

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