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# Please solve with all steps, thank you!

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(x-3)/3 = -4+(1/2)

#1
+7348
+1

$$\frac{x-3}{3}\,=\,-4+\frac12$$

Multiply both sides of the equation by  3  .

$$x-3\,=\,3(-4)+3(\frac12) \\~\\ x-3\,=\,-12+\frac32$$

Add  3  to both sides of the equation.

$$x\,=\,-12+\frac32+3$$

Get a common denominator on the right side and combine the fractions.

$$x\,=\,\frac{-12(2)}{2}+\frac{3}{2}+\frac{3(2)}{2} \\~\\ x\,=\,\frac{-24}{2}+\frac{3}{2}+\frac{6}{2} \\~\\ x\,=\,\frac{-24+3+6}{2}\\~\\ x\,=\,-\frac{15}{2}$$

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Oct 3, 2017

#1
+7348
+1

$$\frac{x-3}{3}\,=\,-4+\frac12$$

Multiply both sides of the equation by  3  .

$$x-3\,=\,3(-4)+3(\frac12) \\~\\ x-3\,=\,-12+\frac32$$

Add  3  to both sides of the equation.

$$x\,=\,-12+\frac32+3$$

Get a common denominator on the right side and combine the fractions.

$$x\,=\,\frac{-12(2)}{2}+\frac{3}{2}+\frac{3(2)}{2} \\~\\ x\,=\,\frac{-24}{2}+\frac{3}{2}+\frac{6}{2} \\~\\ x\,=\,\frac{-24+3+6}{2}\\~\\ x\,=\,-\frac{15}{2}$$

hectictar Oct 3, 2017