Please solve with all steps, thank you!

\(\frac{x-3}{3}\,=\,-4+\frac12\)

                                             Multiply both sides of the equation by  3  .

\(x-3\,=\,3(-4)+3(\frac12) \\~\\ x-3\,=\,-12+\frac32\)

                                             Add  3  to both sides of the equation.

\(x\,=\,-12+\frac32+3\)

                                             Get a common denominator on the right side and combine the fractions.

\(x\,=\,\frac{-12(2)}{2}+\frac{3}{2}+\frac{3(2)}{2} \\~\\ x\,=\,\frac{-24}{2}+\frac{3}{2}+\frac{6}{2} \\~\\ x\,=\,\frac{-24+3+6}{2}\\~\\ x\,=\,-\frac{15}{2}\)