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Solve $2^{6x} + 2^{3x + 2} = 21$

Guest May 26, 2020

1⁺⁰ Answers

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Let $u=2^{3x}$ then the equation can be rewritten as $u^2+4u-21=0$

This factorises as: (u + 7)(u - 3) = 0

Can you take it from here?

Alan May 26, 2020

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