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 Please tell me how many sig figs with the answer thanks

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5. A 3 kg object sits on the floor of an unknown material. the coefficient of kinetic friction between them is 0.85. What applied force is required to accelerate the block to 0.15 m/s2

 Sep 2, 2015

4+0 Answers

 #1
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You MUST have a formula in your book to calculate these things. You should always give the formula. Some of us haven't done this stuff for decades, so we have forgotten!. Sorry.

 Sep 2, 2015
 #2
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The formula is F=UFN

 Sep 2, 2015
 #3
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OK. But when you give a formula, you must always explain what the letters stand for. For example F=Force, c=speed of light.......and so on.

 Sep 2, 2015
 #4
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The resistive force is (coefficient of friction)*mass*(gravitational acceleration), so the net force (F) minus this resistive force must equal mass*acceleration; or:

 

F - 0.85*3*9.81 = 3*0.15

 

F = 3*0.15 + 0.85*3*9.81

 

F = 25.47 Newtons

 Sep 2, 2015

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