e^x-1 = 4 solve the equation
\(e^x -1 = 4\\ e^x = 5\\ x = \ln(5)\)
This might also be
e^(x - 1) = 4 take the Ln of both sides
Ln e^(x - 1) = Ln (4) and we can write
(x - 1) Ln e = Ln (4) Ln e = 1.....so we can ignore this
x - 1 = Ln (4) add 1 to both sides
x = Ln (4) + 1 ≈ 2.386
I wouldn't let it be \(e^{x-1}\) without a thorough scolding about using parentheses!
Pretty rampant parenthetical lack on this site !
Eh.....as EP said......many on here consider parentheses/brackets to be unnecessary "frills"
But they are not frills, they are important !!! :)
+128475 
