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e^x-1 = 4 solve the equation

 Feb 4, 2019
 #1
avatar+5088 
+1

\(e^x -1 = 4\\ e^x = 5\\ x = \ln(5)\)

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 Feb 4, 2019
 #2
avatar+100570 
+1

This might also be

 

e^(x - 1) = 4      take the Ln of both sides

 

Ln e^(x - 1) = Ln (4)      and we can write

 

(x - 1) Ln e =  Ln (4)          Ln e = 1.....so we can ignore this

 

x - 1 = Ln (4)     add 1 to both sides

 

x =  Ln (4) + 1   ≈   2.386

 

 

cool cool cool

 Feb 4, 2019
 #3
avatar+5088 
+1

I wouldn't let it be \(e^{x-1}\) without a thorough scolding about using parentheses!

Rom  Feb 4, 2019
 #4
avatar+18360 
+1

Pretty rampant parenthetical lack on this site !  cheeky

ElectricPavlov  Feb 4, 2019
 #5
avatar+100570 
+1

Eh.....as EP said......many on here consider parentheses/brackets to be unnecessary "frills"

 

cool cool cool

CPhill  Feb 5, 2019
 #6
avatar+100819 
0

But they are not frills,  they are important   !!!  :)

Melody  Feb 5, 2019
edited by Melody  Feb 5, 2019

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