e^x-1 = 4 solve the equation

\(e^x -1 = 4\\ e^x = 5\\ x = \ln(5)\)

This might also be

e^(x - 1) = 4 take the Ln of both sides

Ln e^(x - 1) = Ln (4) and we can write

(x - 1) Ln e = Ln (4) Ln e = 1.....so we can ignore this

x - 1 = Ln (4) add 1 to both sides

x = Ln (4) + 1 ≈ 2.386

I wouldn't let it be \(e^{x-1}\) without a thorough scolding about using parentheses!

Pretty rampant parenthetical lack on this site !

Eh.....as EP said......many on here consider parentheses/brackets to be unnecessary "frills"

But they are not frills, they are important !!! :)