(-x+6x^3)/(3x-2)=?
(10x^3+3x^2+7x-1)/(2x^2+x+1)=?
(6 x^3)/(3 x-2)-x/(3 x-2) (in expanded form)
Roots are:x = 1/sqrt(6) and -1/sqrt(6) and x=0
Alternate form:
x (3/(2 x^2+x+1)+5)-1
Real root:x=0.13209
