+33615 I guess this should look like: \(\frac{2x-2}{x^2-x-12}\)
If so, it can be written as \(\frac{2x-2}{(x-4)(x+3)}\)
Express as partial fractions: \(\frac{2x-2}{(x-4)(x+3)} = \frac{A}{x-4}+\frac{B}{x+3}\)
from which we find
\(A + B = 2\\\\3A-4B=-2\)
i'll leave you to find A and B.
