The sum of the first n terms of the geometric sequenece 1/4, 1/8, 1/16, ... is 63/128. Find n.
Sumn = a(rn-1) / (r-1) a = 1/4 r = 1/2 Sum = 63/128
sub in these values and solve for 'n'..... Let me know if you get stuck
+36916 
