Simplify the following
(a) \(\sqrt{147a^4}\)
(b) \(\sqrt{80n}\)
(c) \(-7 \sqrt{75x^4}\)
+680 (a) we can first note that 147 is divisible by 49 (7*7*3) and a^4 can come out a^2 so out of the square root comes 7a^2. Your answer is \(\boxed{7a^2\sqrt3}\)
(b) 80 is divisible by 16 (4*4*5) so the answer is \(\boxed{4\sqrt{5n}}\)
(c) 75 is divisible by 25 (5*5*3) and x^4 can come out x^2 so your answer is (don't forget the -7) \(\boxed{-35x^2\sqrt{3}}\)
