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# pleez help

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Simplify the following

(a) $$\sqrt{147a^4}$$

(b) $$\sqrt{80n}$$

(c) $$-7 \sqrt{75x^4}$$

Jul 19, 2020

#1
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(a) we can first note that 147 is divisible by 49 (7*7*3) and a^4 can come out a^2 so out of the square root comes 7a^2. Your answer is $$\boxed{7a^2\sqrt3}$$

(b) 80 is divisible by 16 (4*4*5) so the answer is $$\boxed{4\sqrt{5n}}$$

(c) 75 is divisible by 25 (5*5*3) and x^4 can come out x^2 so your answer is (don't forget the -7) $$\boxed{-35x^2\sqrt{3}}$$

Jul 19, 2020