pleez, i need help

In a right triangle.....one angle is 90^o      the other two add to 90^o

   in ratio of 3 to 7     one is   3 /(3+7) = 3/10^ths   of 90      3/10 x 90 = 27^o

                          and the other is   7/(3+7) = 7/10^ths   of 90 =               63^o

 

 

2 the angles add to 90

     x = one     the other is    2x -30

x    +    2x-30   = 90

 x =40          one angle is 40^o    the other   is    2x-30   =   50^o