+118723 What is the center of the circle x2 + y2 + 8x - 12y + 27 = 0?
What you need to do is complete the squares
\(x^2 + y^2 + 8x - 12y + 27 = 0\\ x^2 + y^2 + 8x - 12y=-27\\ (x^2 + 8x+ number1)+ (y^2 - 12y+number2)=-27+number 1 +number2\\ \)
You have to find the numbers that turn those expressions into perfect squares.
Can you do that?
