+129899 1) -1x^2 - x = 3 = 0
Possible rational roots = all the possible factors of -3 over all the possible factors of -1 = ±1, ± 3
2) 2x^3 + 2x^2 - 19x + 20 = 0
Well...by cheating...[looking at the answers]....I can see that one root is -4
So....using some synthetic division....we can find the remaining polynomial
-4 [ 2 2 - 19 20 ]
-8 24 -20
------------------------
2 -6 5 0
So....the remaining polynomial is 2x^2 - 6x + 5
And using the quadratic formula, the other two roots are
x = ( 6 ± √[ 36 - 40] ) / [2(2)] = [ 3 ± i ] / 2
