In triangle ABC, AB = BC = 17 and AC = 16. Find the inradius of triangle ABC.
Please help!
Thanks in advance!
Actually you forgot to multiply by two(but good job)
\(r = \frac{[ABC]}{s} = \frac{120}{(17+17+16)/2} = \boxed{\frac{24}{5}}.\)
I think that's the answer?