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Consider p(x)=ax^2-5x+6 and q(x)=bx^2+3x-2.

If p(x) * q(x) has a 20x^3 term and a 30x^2 term, determine a+b.

 Aug 6, 2023

Best Answer 

 #1
avatar+183 
+3

We have \(p(x)q(x)=(ax^2-5x+6)(bx^2+3x-2)\), so \(20=3a-5b\) and \(30=-2a+6b-15\). Solving the system of equations gives \(a=43.125\) and \(b=21.875\), so \(a+b=65\).

 Aug 6, 2023
 #1
avatar+183 
+3
Best Answer

We have \(p(x)q(x)=(ax^2-5x+6)(bx^2+3x-2)\), so \(20=3a-5b\) and \(30=-2a+6b-15\). Solving the system of equations gives \(a=43.125\) and \(b=21.875\), so \(a+b=65\).

plaintainmountain Aug 6, 2023
 #2
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Thank you so muchh!! smiley

dumplings  Aug 6, 2023

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