Consider p(x)=ax^2-5x+6 and q(x)=bx^2+3x-2.
If p(x) * q(x) has a 20x^3 term and a 30x^2 term, determine a+b.
+183 We have \(p(x)q(x)=(ax^2-5x+6)(bx^2+3x-2)\), so \(20=3a-5b\) and \(30=-2a+6b-15\). Solving the system of equations gives \(a=43.125\) and \(b=21.875\), so \(a+b=65\).
+183 We have \(p(x)q(x)=(ax^2-5x+6)(bx^2+3x-2)\), so \(20=3a-5b\) and \(30=-2a+6b-15\). Solving the system of equations gives \(a=43.125\) and \(b=21.875\), so \(a+b=65\).
