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You take the four Aces, four $2$'s, and four $3$'s from a standard deck of 52 cards, forming a set of $12$ cards. You then deal all $12$ cards at random to four players, so that each player gets three cards. What is the probability that each player gets an Ace, a $2$, and a $3$?

I am completely stuck, any hints were to start?

 Jun 15, 2020
 #1
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i think u should go to that brainly site



it has le answer!

 Jun 15, 2020
 #3
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Great question!  The probability is 4!*4!*4!*4!/12! = 4/5775.

 Jun 15, 2020
 #4
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The brainly site is not correct. I put in your answer the guest and It was wrong.

 Jun 15, 2020

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