write a system of 3 equations and 3 variables that has the unique solution of (-1,1,2).
Hello Guest!
\(x+y+z=2\)
\(x y-z=-3\)
\(x+y+z^2=4\)
!
I prove it
\(x+y+z=2\\ xy-z=-3\\ x+y+z^2=4 \)
\(x=-1\\ y=1\\ z=2\)
\(-1+1+2=2\\ -1\cdot 1-2=-3\\ -1+1+2^2=4 \)
q.e.d.
Mistake!The question asks for a unique solution. The equations are solved by both x = -1, y = 1, z = 2 and x = 1, y = -1, z = 2.The correction follows.