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# Pls help. Do give me detailed amd explained steps on the workings. Thank you so much in advance.

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Kate had three boxes, A, B and C, containing a total of 1512 necklaces.

The number of necklaces in Box A to the total number of necklaces was 2:7.

Kate sold 190 necklaces from Box B and sold 1/4 of the necklaces in Box C.

The number of necklaces left in Box B to the number of necklaces left in Box C was 2:1.

How many necklaces were there in Box C at first?

Oct 26, 2021

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Hello I can't help you but I want to tell you that you can do it I believe in you have a good day

You can do it

Oct 26, 2021
edited by Guest  Oct 26, 2021
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Not funny

Guest Oct 26, 2021
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A + B + C ==1512 necklaces.

A / 1512 ==2 / 7, solve for A

A ==432 Necklacesin box A

1512   -  432 ==1,080 Necklaces in box B + C

[B - 190] ==Necklaces left in box B

[C  - 1/4C] ==3/4C - Necklaces left in box C

B  +  C  ==1080..........................(1)

[B - 190] / [3/4C] ==2/1............(2), solve for B, C

B==724  and  C ==356 - number of necklaces in box C at first.

Oct 26, 2021