Kate had three boxes, A, B and C, containing a total of 1512 necklaces.
The number of necklaces in Box A to the total number of necklaces was 2:7.
Kate sold 190 necklaces from Box B and sold 1/4 of the necklaces in Box C.
The number of necklaces left in Box B to the number of necklaces left in Box C was 2:1.
How many necklaces were there in Box C at first?
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A + B + C ==1512 necklaces.
A / 1512 ==2 / 7, solve for A
A ==432 Necklacesin box A
1512 - 432 ==1,080 Necklaces in box B + C
[B - 190] ==Necklaces left in box B
[C - 1/4C] ==3/4C - Necklaces left in box C
B + C ==1080..........................(1)
[B - 190] / [3/4C] ==2/1............(2), solve for B, C
B==724 and C ==356 - number of necklaces in box C at first.
