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How many distinct permutations of the letters in ARRANGE are there?

 Mar 11, 2021
 #1
avatar+118069 
+2

distinct permutaions = 

 

Number of letters  !   /   [  (Repeats ) !  ]   =

 

7!   /   [   ( repeats of A)!  ( repeats of R)!     ]  =

 

7!  / [ 2!  * 2!   ]  = 

 

5040  /  4  =

 

1260  distinct permutations

 

cool cool cool

 Mar 11, 2021
 #2
avatar+550 
+1

thank you

xxJenny1213xx  Mar 11, 2021

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