A crate with a mass of 500kg is lifted from rest with a uniform acceleration by a crane such that after 5 seconds it has a velocity of 8 m/s. Calculate the tension (force) in the cable.
+14986 Pls help i don't understand this..
A crate with a mass of 500kg is lifted from rest with a uniform acceleration by a crane such that after 5 seconds it has a velocity of 8 m/s. Calculate the tension (force) in the cable.
\(a=\frac{v}{t}=\frac{8m/s}{5s}=1.6m/s^2\)
\(F=m\times( a+g)=500kg\times (1.6+9.81)m/s^2\times\frac{Ns^2}{kgm}\)
\(F=5705N\)
\(The \ pulling \ force \ in \ the \ cable \ is \ 5705 N.\)
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