Simplify (1 + i√3)^6
We can write [(1 + \sqrt{-3})^6 = (1 + i \sqrt{3})^6.]Let z=1+i3. Then z2=1+2i3+3=4i3, so z3=−3i, and z6=z3z3 =−3i(−3i) =9.
Therefore, (1+i*sqrt(3))^6 = 9 .
