Factor a^3 + 2a^2 - 9a - 18 by grouping its terms properly
Let f(a)=a3+2a2−9a−18
⇒ (a + 2) is a factor of f(a)
So dividing f(a) by (a+2) we get
f(a)=(a+2)(a2−9)
=(a+2)(a+3)(a−3)
∴ Factors = -2, 3, -3