+0  
 
0
45
1
avatar

Factor a^3 + 2a^2 - 9a - 18 by grouping its terms properly

 Jun 18, 2021
 #1
avatar+505 
+1

Let  \(f(a) = a^3+2a^2-9a-18\)

⇒ (a + 2) is a factor of f(a) 

So dividing f(a) by (a+2) we get 

 

\(f(a) = (a+2)(a^2-9)\)

         \(=(a+2)(a+3)(a-3)\)

 

∴ Factors = -2, 3, -3

 Jun 19, 2021

25 Online Users

avatar
avatar