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Factor a^3 + 2a^2 - 9a - 18 by grouping its terms properly

 Jun 18, 2021
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Let  f(a)=a3+2a29a18

⇒ (a + 2) is a factor of f(a) 

So dividing f(a) by (a+2) we get 

 

f(a)=(a+2)(a29)

         =(a+2)(a+3)(a3)

 

∴ Factors = -2, 3, -3

 Jun 19, 2021

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