Factor a^3 + 2a^2 - 9a - 18 by grouping its terms properly
Let \(f(a) = a^3+2a^2-9a-18\)
⇒ (a + 2) is a factor of f(a)
So dividing f(a) by (a+2) we get
\(f(a) = (a+2)(a^2-9)\)
\(=(a+2)(a+3)(a-3)\)
∴ Factors = -2, 3, -3
+526 
