Find the area of the region enclosed by the graph of x^2+y^2=2x-6y+6+4x-4y+12

gaberiellz Apr 23, 2024

#1**+1 **

Simplify as

x^2 -6x + y^2 +10y = 12 + 6 complete the square on x, y

x^2 - 6x + 9 + y^2 + 10y + 25 = 12 + 6+ 9 + 25

(x - 3)^2 + (y + 5)^2 = 52

Ths is a circle with r^2 = 52

Area = pi * r^2 = 52 pi

CPhill Apr 23, 2024

#2**0 **

it seems that you completed the square wrong, you are supposed to get (x-3)^2 and (y-5)^2. After that part, I am stuck though

gaberiellz
Apr 23, 2024