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If P=9^x, then find 3^2x+3 in terms of P

 Jan 15, 2017

Best Answer 

 #3
avatar+37095 
+10

...although Alan's and my answers are the same mathematically...his is w-a-a-ay simpler !

 

beacuse     3 ^(2.0959 logP) + 3

               = ( 3  ^2.0959)^(LogP) + 3

               = 10 ^ log P

               = P + 3                            Not sure why I didn't see this origianlly....needed Alan's jumpstartt, I guess

 Jan 16, 2017
 #1
avatar+37095 
+10

P= 9^x

Log P = x log 9

Log P/Log 9 = x

1.04795 Log P = x      SUb this into the second equation

 

3^(2x) +3

3^(2(1.04795 LogP)) +3

3^(2.0959 Log P)  + 3 

 Jan 15, 2017
edited by ElectricPavlov  Jan 15, 2017
 #3
avatar+37095 
+10
Best Answer

...although Alan's and my answers are the same mathematically...his is w-a-a-ay simpler !

 

beacuse     3 ^(2.0959 logP) + 3

               = ( 3  ^2.0959)^(LogP) + 3

               = 10 ^ log P

               = P + 3                            Not sure why I didn't see this origianlly....needed Alan's jumpstartt, I guess

ElectricPavlov  Jan 16, 2017
 #2
avatar+33653 
+10

P = 9^x

 

3^(2x) + 3 → (3^2)^x + 3 → 9^x + 3 → P + 3

 

3^(2x+3) →  (3^(2x))*3^3 → (9^x)*27 → 27P

.

 Jan 15, 2017
 #4
avatar+37095 
+10

...although Alan's and my answers are the same mathematically...his is w-a-a-ay simpler !

 

beacuse     3 ^(2.0959 logP) + 3

               = ( 3  ^2.0959)^(LogP) + 3

               = 10 ^ log P    + 3                   (sorry.....didn't proof read before 'enter')

               = P + 3                            Not sure why I didn't see this origianlly....needed Alan's jumpstartt, I guess

 Jan 16, 2017

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