...although Alan's and my answers are the same mathematically...his is w-a-a-ay simpler !
beacuse 3 ^(2.0959 logP) + 3
= ( 3 ^2.0959)^(LogP) + 3
= 10 ^ log P
= P + 3 Not sure why I didn't see this origianlly....needed Alan's jumpstartt, I guess
P= 9^x
Log P = x log 9
Log P/Log 9 = x
1.04795 Log P = x SUb this into the second equation
3^(2x) +3
3^(2(1.04795 LogP)) +3
3^(2.0959 Log P) + 3
...although Alan's and my answers are the same mathematically...his is w-a-a-ay simpler !
beacuse 3 ^(2.0959 logP) + 3
= ( 3 ^2.0959)^(LogP) + 3
= 10 ^ log P
= P + 3 Not sure why I didn't see this origianlly....needed Alan's jumpstartt, I guess
P = 9^x
3^(2x) + 3 → (3^2)^x + 3 → 9^x + 3 → P + 3
3^(2x+3) → (3^(2x))*3^3 → (9^x)*27 → 27P
.
...although Alan's and my answers are the same mathematically...his is w-a-a-ay simpler !
beacuse 3 ^(2.0959 logP) + 3
= ( 3 ^2.0959)^(LogP) + 3
= 10 ^ log P + 3 (sorry.....didn't proof read before 'enter')
= P + 3 Not sure why I didn't see this origianlly....needed Alan's jumpstartt, I guess