#1**-1 **

Let the height of triangle ABC be h.

[asy]

pair A, B, C, D, E;

A = (0,0);

B = (16,0);

C = (8,h);

D = (0,h-5);

E = (16,h-11);

draw(A--B--C--cycle);

draw(D--E);

draw(A--D,dashed);

draw(B--E,dashed);

label("A", A, SW);

label("B", B, SE);

label("C", C, N);

label("D", D, SW);

label("E", E, SE);

label("5", (A+D)/2, W);

label("11", (B+E)/2, E);

label("h", (C+D)/2, W);

label("h−5", (C+E)/2, E);

[/asy]

Since the shaded portions have the same area, we have the following equation:

(1/2) * 11 * h = (1/2) * (h - 5) * 16

Solving for h, we get:

h = 15

Therefore, the height of triangle ABC is 15 units.

bingboy Oct 12, 2023

#4**+1 **

TYSM!! @Alan! It's correct. Also, thanks for leaving some of the work for me to solve. Really appreciate it.

totalkoolnezz Oct 12, 2023