Find the constant \(a\) such that
\((x^2 - 3x + 4)(2x^2 +ax + 7) = 2x^4 -11x^3 +30x^2 -41x +28\)
Expanding, we get that the coefficient of a is -3a + 28 = -41, so a = 23.
ahh tht answer is wrong thanks for ur help thoguh!
4ax - 21x = -41x
(4a-21) x = - 41 x
4a - 21 = -41
4a = -20
a = -5