Find the constant a such that
(x2−3x+4)(2x2+ax+7)=2x4−11x3+30x2−41x+28
Expanding, we get that the coefficient of a is -3a + 28 = -41, so a = 23.
ahh tht answer is wrong thanks for ur help thoguh!
4ax - 21x = -41x
(4a-21) x = - 41 x
4a - 21 = -41
4a = -20
a = -5
+19 
