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The mass of sugar in container A was 1/4 the mass of sugar in container B. After 2.25 kg of the sugar in container A and 14 kg 400 g of sugar in container B was used, the mass of sugar in container A was 1/2 the mass of sugar in container B. What was the total mass of sugar in container A and B at first?

 Apr 24, 2022
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Let the mass of sugar in container B==M
The mass of sugar in container A ==1/4M


[M - 14.4] / [1/4M - 2.25] ==2, solve for M


M ==99/5 ==19.80 kg - mass of the sugar in container B at first.
1/4 * 19.80 ==4.95 kg - mass of the sugar in container A at first.

 Apr 24, 2022

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