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\(If\ a = 4, b = 2, and\ c = -5, then\ what\ is\ the\ value\ of\ \sqrt[3]{4a^4b^5} + \dfrac{a - c}{(b+c)^2}?\)

 Jul 13, 2018
edited by Dr.Amione  Jul 13, 2018
 #1
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Just sub the values of the 3 variable and simplify:

 

(4 a^4 b^5)^(1/3) + (a - c)/(b + c)^2 where a = 4, b = 2, c = -5

          32                    +     1 / 1

=33

 Jul 13, 2018

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