Find the product of all constants t such that the quadratic x^2 + tx - 9 can be factored in the form (x+a)(x+b), where a and b are integers.
(x - 1)(x + 9) = x^2 + 8x - 9
(x + 1)(x - 9) = x^2 - 8x + 9
Answer = (8)(-8) = -64
+1072 If t could be 0, then you have
(x+1)(x-9)=x^2-8x-9
(x-1)(x+9)=x^2+8x-9
(x+3)(x-3)=x^2-9
(x-3+(x+3)=x^2-9
0*0*8*-8=0
