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Find the product of all constants t such that the quadratic x^2 + tx - 9 can be factored in the form (x+a)(x+b), where a and b are integers.

 Mar 14, 2020
 #1
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(x - 1)(x + 9) = x^2 + 8x - 9

(x + 1)(x - 9) = x^2 - 8x + 9

 

Answer = (8)(-8) = -64

 Mar 14, 2020
 #2
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Sorry, but that is incorrect... PLS HELP!!! anybody else??

 Mar 14, 2020
 #3
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If t could be 0, then you have

 

(x+1)(x-9)=x^2-8x-9

(x-1)(x+9)=x^2+8x-9

(x+3)(x-3)=x^2-9

(x-3+(x+3)=x^2-9

 

0*0*8*-8=0

 Mar 14, 2020

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