Find the area of the region satisfying the inequality x^2 + y^2 \(\leq\) 4x + 6y + 13
+36916 This is a circle equation
x^2 -4x + y^2 - 6y <= 13 complete the square for x and y
(x-2)^2 + ( y-3)^2 <= 13 + 4 + 9 < ======== this is r2
26 = r^2 area of circle = pi r^2 = 26 pi
