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Find the area of the region satisfying the inequality x^2 + y^2 \(\leq\) 4x + 6y + 13

 Mar 6, 2021
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This is a circle equation

x^2 -4x       + y^2 - 6y     <= 13     complete the square for  x  and  y

(x-2)^2       + ( y-3)^2     <=   13  + 4 + 9  < ======== this is r2

                                                               26 = r^2                  area of circle = pi r^2 =   26 pi

 Mar 6, 2021

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