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Find the discriminant of the quadratic \(5x^2 - 2x + 8.\)

 Apr 2, 2020
 #1
avatar+36916 
+2

Here is the Quadratic Formula:

 

\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)       the   b^2-4ac   part is the discriminant      5x^2 -2x+8        a = 5        b = -2      c= 8

                                                                 plug in those values and compute !  cheeky

 Apr 2, 2020
 #2
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0

I got -164 which was incorrect. I did -2^2 - 4(5)(8) and got -164. Can you try again?

Guest Apr 2, 2020
 #3
avatar+36916 
+2

b^2 - 4ac    would be   (-2)^2 - 4 (5)(8) =   4 - 160 =  -  156   

ElectricPavlov  Apr 2, 2020
 #4
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0

Oh! Thank you thank you so much!

Guest Apr 3, 2020

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