Find the sum of the x values which solve the system of equations below.
3y-49=0
x^2+Y^2-281=0
thank you
+128407 3y - 49 =0
3y = 49
y = 49/3
Subbing this into the second equation we have that
x^2 + (49/3)^2 - 281 = 0
x^2 + 2401/ 9 - 281 = 0 multiply through by 9
9x^2 + 2401 - 2529 = 0
9x^2 - 128 = 0
9x^2 = 128 divide both sides by 9
x^2 = 128 / 9
x^2 = 2 (64/9) take both roots
x = ± (8/3)√2
Of course, the sum of these x values = 0
