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Find the sum of the x values which solve the system of equations below.
3y-49=0

x^2+Y^2-281=0

 

thank you 

 May 14, 2020
 #1
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3y - 49  =0

 

3y = 49

 

y =  49/3

 

Subbing this into the second equation we have that

 

x^2 +  (49/3)^2  -  281  =  0

 

x^2  + 2401/ 9  - 281  = 0     multiply through by   9

 

9x^2  + 2401  - 2529  = 0

 

9x^2  - 128  = 0

 

9x^2  = 128       divide both sides by 9

 

x^2  =  128 / 9

 

x^2  =  2  (64/9)     take  both roots

 

x = ± (8/3)√2

 

Of course,  the sum of these x values =   0

 

 

cool cool cool

 May 14, 2020

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