George bought 6 identical shoes and 3 identical shirts for $348 if 2 pairs of shoes costs 3 times as much as a shirt ,find the cost of 25 such shirts.
Given: 2 shoes = 3 shirts and 6 shoes + 3 shirts = 348
Substitute:
3 shirts (3) + 3 shirts = 348
shirt = 29
then 25 shirts = 25 x 29 = 725.
(I should clarify that I ASSUMED ' George bought 6 identical shoes' means '6 PAIRS' of shoes in my calculation)
If the cost of 1 shoe =S, and:
The cost of 1 shirt =s, then:
4S =3s, then:
s =4S/3, but we have:
6S +3s =348. Sub s into this..............(1)
6S + 3(4S/3) =348
6S + 4S = 348
10S = 348
S=$34.80 - cost of 1 shoe, and:..............(2)
s =(4*34.80)/3
s=$46.40 - cost of 1 shirt. So that:..............(3)
4 shoes(2pairs)*$34.80 =3 shirts * $46.40
$139.20 = $139.20, and subbing (2) and (3) into 1 above, we have:
6*$34.80 + 3*$46.40 =348
$208.80 + $139.20 = $348.00, Therefore the cost of 25 shirts would be:
25 x $46.40 =$1,160.00