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# pls help

0
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y=8ax^3+6/x

y has a minimum value when x=0.5

work out the value of a

Apr 30, 2022

#1
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Can you put that in TeX or at least add parenthesis? I can't tell if you mean $$y=$$ $$8ax³+6\over x$$$$8ax³+6/x$$ , $$8ax^{3+6/x}$$ , or something else entirely.

Apr 30, 2022
#2
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y=(8ax^3)+(6/x)

Apr 30, 2022