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y=8ax^3+6/x

y has a minimum value when x=0.5

work out the value of a

 Apr 30, 2022
 #1
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Can you put that in TeX or at least add parenthesis? I can't tell if you mean \(y=\) \(8ax³+6\over x\)\(8ax³+6/x\) , \(8ax^{3+6/x}\) , or something else entirely.

 Apr 30, 2022
 #2
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y=(8ax^3)+(6/x)

 Apr 30, 2022

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