Given r=−b+√b2−4ac2a and s=−b−√b2−4ac2a. What is the value of $r+s$, simplified in terms of $a, b$, and $c$?
r and s are both the roots of the polynomial ax2+bx+c, so r+s is just the sum of the 2 roots. According to Vieta's formulas, that is equal to −ba