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In the figure below, side $AE$ of rectangle $ABDE$ is parallel to the $x$-axis, and side $BD$ contains the point $C$. The vertices of triangle $ACE$ are $A(1, 1)$, $C(3, 3)$ and $E(4, 1)$. What is the ratio of the area of triangle $ACE$ to the area of rectangle $ABDE$? Express your answer as a common fraction.

 Jun 18, 2021
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Area of  ACE  = (1/2) (AE) ( AB)  =  (1/2) (4) (3)  =   6

 

Area of  rectangle  =   (AB) ( AE)  =  (3) (4)   =12

 

Ratio of areas  = 6 / 12  =   1/ 2

 

 

cool cool cool

 Jun 18, 2021

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